未看题解完成，用时 26min 18s。
有一个简单的贪心策略是直接把每个位置都拆开得到 个长度为 的数字然后直接加起来，但是这个贪心显然是错的。
考虑直接错上加错，以一定概率把两个长度为 的数字合并起来（实测概率取 可以通过）然后再加起来合并，就可以通过这题。
成功率不太会算，但是这一看就很不能卡 :)
CF852A Digits 题解
发布于 2026-03-11 22:56 129 字 1 min read
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题解CF1943C Tree Compass 题解CF837E Vasya's Function 题解AT_arc149_c [ARC149C] Avoid Prime Sum 题解CF629D Babaei and Birthday Cake 题解CF1042F Leaf Sets 题解CF97D Robot in Basement 题解AT_arc193_a [ARC193A] Complement Interval Graph 题解P11604 [PA 2016] 卡牌 / Gra w karty 题解CF812E Sagheer and Apple Tree 题解CF1310D Tourism 题解CF1693C Keshi in Search of AmShZ 题解CF1137B Camp Schedule 题解CF1270E Divide Points 题解CF1029E Tree with Small Distances 题解CF1943B Non-Palindromic Substring 题解CF446D DZY Loves Games 题解CF1592F2 Alice and Recoloring 2 题解CF1839E Decreasing Game 题解CF1732D2 Balance (Hard version) 题解CF1732D1 Balance (Easy version) 题解CF1981D Turtle and Multiplication 题解CF40E Number Table 题解CF51E Pentagon 题解CF732F Tourist Reform 题解CF793C Mice problem 题解CF126D Fibonacci Sums 题解CF1705E Mark and Professor Koro 题解CF425D Sereja and Squares 题解CF300E Empire Strikes Back 题解CF364C Beautiful Set 题解CF898F Restoring the Expression 题解CF908G New Year and Original Order 题解CF460D Little Victor and Set 题解CF895E Eyes Closed 题解CF1967C Fenwick Tree 题解CF607C Marbles 题解CF1411E Poman Numbers 题解CF1623D Robot Cleaner Revisit 题解CF178F3 Representative Sampling 题解CF1605D Treelabeling 题解CF2056D Unique Median 题解CF1983F array-value 题解CF1238E Keyboard Purchase 题解CF1553F Pairwise Modulo 题解CF484B Maximum Value 题解CF1470D Strange Housing 题解CF1498E Two Houses 题解CF1923E Count Paths 题解CF2049E Broken Queries 题解CF147B Smile House 题解CF1712E1 LCM Sum (easy version) 题解CF1646E Power Board 题解AT_tdpc_tree 木 题解AT_tdpc_lexicographical 辞書順 题解CF2036G Library of Magic 题解CF1834D Survey in Class 题解CF1884D Counting Rhyme 题解CF1886D Monocarp and the Set 题解CF1617D1 Too Many Impostors (easy version) 题解CF1780D Bit Guessing Game 题解CF1804D Accommodation 题解CF1796D Maximum Subarray 题解CF2030B Minimise Oneness 题解CF2030D QED's Favorite Permutation 题解CF1731E Graph Cost 题解CF1442C Graph Transpositions 题解CF1165F1 Microtransactions (easy version) 题解CF1165F2 Microtransactions (hard version) 题解CF1481D AB Graph 题解AT_joi2018ho_e 毒蛇の脱走 (Snake Escaping) 题解P7670 [JOI 2018 Final] 毒蛇越狱 / Snake Escaping 题解P7669 [JOI 2018 Final] 月票购买 / Commuter Pass 题解AT_joi2018ho_d 定期券 (Commuter Pass) 题解CF1358E Are You Fired? 题解CF1453E Dog Snacks 题解P11078 「FSLOI Round I」迷雾 题解P2998 [USACO10NOV] Candy S 题解P10895 选择困难症 题解CF1619E MEX and Increments 题解CF888D Almost Identity Permutations 题解CF863E Turn Off The TV 题解
未看题解完成，用时 26min 18s。 有一个简单的贪心策略是直接把每个位置都拆开得到 $|s|$ 个长度为 $1$ 的数字然后直接加起来，但是这个贪心显然是错的。 考虑直接错上加错，以一定概率把两个长度为 $1$ 的数字合并起来（实测概率取 $\frac1{15}$ 可以通过）然后再加起来合并，就可以通过这题。 成功率不太会算，但是这一看就很不能卡 :)
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